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x=(5x+5x^2)/x
We move all terms to the left:
x-((5x+5x^2)/x)=0
Domain of the equation: x)!=0We multiply all the terms by the denominator
x!=0/1
x!=0
x∈R
-((5x+5x^2)+x*x)=0
We calculate terms in parentheses: -((5x+5x^2)+x*x), so:We get rid of parentheses
(5x+5x^2)+x*x
Wy multiply elements
(5x+5x^2)+x^2
We get rid of parentheses
5x^2+x^2+5x
We add all the numbers together, and all the variables
6x^2+5x
Back to the equation:
-(6x^2+5x)
-6x^2-5x=0
a = -6; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-6)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-6}=\frac{0}{-12} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-6}=\frac{10}{-12} =-5/6 $
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